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Thread: Calculus: Applications of Derivatives


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    Re: Calculus: Derivatives -help!

    I got confused.

    But yahoo answers have people like you too!
    LOL..

    Last edited by ohhoneyy; 11-11-2009 at 04:25 PM.
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    Re: Calculus: Derivatives -help!

    Vf - Vi = 80 000 - 180 000

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    Re: Calculus: Derivatives -help!

    I think the negative is direction of wateR? LOL not sure

    This is what I did:

    [S(10) - S(0)] / (10-0) = [200(20)^2 - 200(30)^2] / 10 = -10,000
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    Re: Calculus: Derivatives -help!

    ^ yeah I get it now, negative because wter is decresing.
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    Re: Calculus: Derivatives -help!

    ^ It's negative because the water is flowing out.

    Edit: ohhoneyy beat me to it.

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    Re: Calculus: Derivatives -help!

    How fast is the water running at the end of 10min? vinstant = -7 999.8 gallons/min
    Vinst = lim(t->0) [f(a + t) - f(a)]/t = lim(t->0) [f(10 + 0.001) - f(10)]/0.001 ......... then just do math

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    Re: Calculus: Derivatives -help!

    2nd Question now:) (the one on the horse and furlongs)
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    Re: Calculus: Derivatives -help!

    Don't know if you got it yet, but I think Equilateral triangle Area should be (square root 3 s^2 )4 and not cube root?

    If you look at half of the equilateral triangle as a right triangle, you'll have the height, 's' as a side of the equilateral triangle and s/2 on the bottom.

    then Pythagorean theorem should give you h^2 = s^2 - (s/2)^2
    do some algebra and you'll have h = (square root 3 *s)/2
    plug it into A = s * h *1/2 (triangle area) and you should get
    A = (square root 3 * s^2)/4

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    Re: Calculus: Derivatives -help!

    you guys are giving me a headache ><
    laughter is the best medicine:grin:

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    Re: Calculus: Derivatives -help!

    c) What is the approximate speed of the horse as it passes the 3-furlong marker? 16.9 yards/s, 220yards/13s
    d) During which portion of the race is the horse running the fastest? between F9-F10, v=20yards/s
    e) accelerating the fastest? F1-F2, calc velocity at each second, you would see that greatest Δv
    is +5.9y/s^2
    Last edited by jchuu; 11-11-2009 at 06:44 PM.

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